3(x^2-4)=2x^2-1

Solution for 3(x^2-4)=2x^2-1 equation:

Simplifying
3(x2 + -4) = 2x2 + -1

Reorder the terms:
3(-4 + x2) = 2x2 + -1
(-4 * 3 + x2 * 3) = 2x2 + -1
(-12 + 3x2) = 2x2 + -1

Reorder the terms:
-12 + 3x2 = -1 + 2x2

Solving
-12 + 3x2 = -1 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
-12 + 3x2 + -2x2 = -1 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
-12 + 1x2 = -1 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-12 + 1x2 = -1 + 0
-12 + 1x2 = -1

Add '12' to each side of the equation.
-12 + 12 + 1x2 = -1 + 12

Combine like terms: -12 + 12 = 0
0 + 1x2 = -1 + 12
1x2 = -1 + 12

Combine like terms: -1 + 12 = 11
1x2 = 11

Divide each side by '1'.
x2 = 11

Simplifying
x2 = 11

Take the square root of each side:
x = {-3.31662479, 3.31662479}